What is the domain of f(x)= 1/(sqrt(2.1x-6x^2)) ?

The domain of f(x)= 1/(sqrt(2.1x-6x^2)) is 0<x< 7/20

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domain of f(x)= 1/(sqrt(2.1x-6x^2))

domain

f (x) = \frac{1}{2.1 x - 6 x ^{2}}

0 < x < \frac{7}{20}

Interval Notation

(0, \frac{7}{20})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 0.35

Find undefined (singularity) points:

x = 0, x = \frac{7}{20}

Combine real regions and undefined points for final function domain

0 < x < \frac{7}{20}

\frac{5 x + 2}{x - 9}

3 x^{2} - 4 x + 7

- \frac{3}{4} x + 2

f (x) = \frac{x - 6}{x ^{2} + 25}

- 0.002 x + 0.04

What is the domain of f(x)= 1/(sqrt(2.1x-6x^2)) ?
The domain of f(x)= 1/(sqrt(2.1x-6x^2)) is 0<x< 7/20