What is the domain of f(x)=sqrt(x-3x^2) ?

The domain of f(x)=sqrt(x-3x^2) is 0<= x<= 1/3

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domain of f(x)=sqrt(x-3x^2)

domain

f (x) = x - 3 x^{2}

0 \leq x \leq \frac{1}{3}

Interval Notation

[0, \frac{1}{3}]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{1}{3}

The function domain

0 \leq x \leq \frac{1}{3}

f (x) = \frac{3 x - 1}{- 2 x - 6}

f (x) = - x + 1 + 2

f (x) = \frac{x ^{2} - 16}{18 - 2 x ^{2}}

f (x) = ln (3 x - 5)

f (x) = ∣ x + 1 ∣ + ∣ x - 1 ∣

What is the domain of f(x)=sqrt(x-3x^2) ?
The domain of f(x)=sqrt(x-3x^2) is 0<= x<= 1/3