What is the domain of-sqrt(2x-3)+6 ?

The domain of-sqrt(2x-3)+6 is x>= 3/2

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domain of-sqrt(2x-3)+6

domain

- 2 x - 3 + 6

x \geq \frac{3}{2}

Interval Notation

[\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{2}

The function domain

x \geq \frac{3}{2}

f (x) = x^{2} + 12 x + 1

f (x) = \frac{x - 7}{x ^{2} + 36}

5 x - 12

\frac{x ^{2} - 1}{4 x - 5}

f (x) = \frac{x + 3}{x ^{2} - 3 x - 10}