What is the domain of f(x)=(2x)/(x^2+5x+4) ?

The domain of f(x)=(2x)/(x^2+5x+4) is x -1

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domain of f(x)=(2x)/(x^2+5x+4)

domain

f (x) = \frac{2 x}{x ^{2} + 5 x + 4}

x < - 4 or - 4 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 4) \cup (- 4, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 4

The function domain

x < - 4 or - 4 < x < - 1 or x > - 1

f (x) = - x^{2} + 4 x - 10

g (x) = \frac{x - 3}{x ^{2} + 2 x - 15}

\frac{x + 1}{x - 8}

f (x) = (x - 12)^{2}

f (x) = \frac{x}{x ^{2} + 3}

What is the domain of f(x)=(2x)/(x^2+5x+4) ?
The domain of f(x)=(2x)/(x^2+5x+4) is x<-4\lor-4<x<-1\lor x>-1