What is the domain of f(x)= 1/(x^2-2x-35) ?

The domain of f(x)= 1/(x^2-2x-35) is x 7

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domain of f(x)= 1/(x^2-2x-35)

domain

f (x) = \frac{1}{x ^{2} - 2 x - 35}

x < - 5 or - 5 < x < 7 or x > 7

Interval Notation

(- \infty, - 5) \cup (- 5, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 5

The function domain

x < - 5 or - 5 < x < 7 or x > 7

(\frac{3}{4})^{x}

y = 3 x - 7

\frac{x - 4}{x}

f (x) = \frac{x ^{2}}{ln ( x ^{2} )}

\frac{1}{3 x - 7}

What is the domain of f(x)= 1/(x^2-2x-35) ?
The domain of f(x)= 1/(x^2-2x-35) is x<-5\lor-5<x<7\lor x>7