What is the domain of f(x)=sqrt(|x-1|-1) ?

The domain of f(x)=sqrt(|x-1|-1) is x = 2

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domain of f(x)=sqrt(|x-1|-1)

domain

f (x) = ∣ x - 1 ∣ - 1

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

The function domain

x \leq 0 or x \geq 2

\frac{( x ^{5} - 16 x )}{5 x ^{3} - 6 x ^{2} + x}

f (x) = ln (x - 2) - 1

\frac{6 x - 12}{( x - 6 ) ( x + 1 )}

f (x) = 2 (3)^{x + 2}

f (x) = x^{2} - 8 x + 4

What is the domain of f(x)=sqrt(|x-1|-1) ?
The domain of f(x)=sqrt(|x-1|-1) is x<= 0\lor x>= 2