What is the domain of sqrt(x^2-3x)-sqrt(x^2-2x-6) ?

The domain of sqrt(x^2-3x)-sqrt(x^2-2x-6) is x = sqrt(7)+1

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domain of sqrt(x^2-3x)-sqrt(x^2-2x-6)

domain

x^{2} - 3 x - x^{2} - 2 x - 6

x \leq - 7 + 1 or x \geq 7 + 1

Interval Notation

(- \infty, - 7 + 1] \cup [7 + 1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 7 + 1 or x \geq 7 + 1

The function domain

x \leq - 7 + 1 or x \geq 7 + 1

f (x) = \frac{x}{x ^{2} + 4}

x - 4

\frac{e ^{x - 1}}{x}

h (x) = 4 - x^{2}

f (t) = \frac{1}{t + 1}

What is the domain of sqrt(x^2-3x)-sqrt(x^2-2x-6) ?
The domain of sqrt(x^2-3x)-sqrt(x^2-2x-6) is x<=-sqrt(7)+1\lor x>= sqrt(7)+1