What is the domain of f(x)=2+sqrt(4+9x) ?

The domain of f(x)=2+sqrt(4+9x) is x>=-4/9

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domain of f(x)=2+sqrt(4+9x)

domain

f (x) = 2 + 4 + 9 x

x \geq - \frac{4}{9}

Interval Notation

[- \frac{4}{9}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{4}{9}

The function domain

x \geq - \frac{4}{9}

3 x - 3

f (x) = \frac{2 x - 6}{x - 1}

f (x) = \frac{1}{1 + ln ( x - 2 )}

3 - lo g_{10} (x^{2} - 1)

\frac{2}{3 + x}

What is the domain of f(x)=2+sqrt(4+9x) ?
The domain of f(x)=2+sqrt(4+9x) is x>=-4/9