What is the domain of f(x)=((x^2-x))/(sqrt(x^2-1)) ?

The domain of f(x)=((x^2-x))/(sqrt(x^2-1)) is x 1

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domain of f(x)=((x^2-x))/(sqrt(x^2-1))

domain

f (x) = \frac{( x ^{2} - x )}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = tan (\frac{1}{2} x + π) + 1

f (x) = e^{5 x}

f (x) = 7 x + 9

f (x) = \frac{x ^{7} - 4 x ^{6} - 16 x ^{5} + 64 x ^{4}}{x}

f (x) = lo g_{10} (2 - x) + x - 3

What is the domain of f(x)=((x^2-x))/(sqrt(x^2-1)) ?
The domain of f(x)=((x^2-x))/(sqrt(x^2-1)) is x<-1\lor x>1