What is the domain of y=(sqrt(x))/(x-1) ?

The domain of y=(sqrt(x))/(x-1) is 0 1

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domain of y=(sqrt(x))/(x-1)

domain

y = \frac{x}{x - 1}

0 \leq x < 1 or x > 1

Interval Notation

[0, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x > 1

f (x) = x^{2} - x + 6 + 1, - 1 \leq x < 4

\frac{x - 4}{x ^{2} + 9}

tan (t)

\frac{x}{7 x - 2}

f (x) = \frac{4}{x + 7}

What is the domain of y=(sqrt(x))/(x-1) ?
The domain of y=(sqrt(x))/(x-1) is 0<= x<1\lor x>1