What is the domain of f(x)=((x^2-x-12))/(25-x^2) ?

The domain of f(x)=((x^2-x-12))/(25-x^2) is x 5

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domain of f(x)=((x^2-x-12))/(25-x^2)

domain

f (x) = \frac{( x ^{2} - x - 12 )}{25 - x ^{2}}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

ln (8 - x^{3})

f (x) = ln (x^{2} + 2 x - 3)

8 + x

f (x) = 5 x 4 x - x^{2}

\frac{x}{x - 4}

What is the domain of f(x)=((x^2-x-12))/(25-x^2) ?
The domain of f(x)=((x^2-x-12))/(25-x^2) is x<-5\lor-5<x<5\lor x>5