What is the domain of (6x)/(x^2-2x) ?

The domain of (6x)/(x^2-2x) is x 2

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domain of (6x)/(x^2-2x)

domain

\frac{6 x}{x ^{2} - 2 x}

x < 0 or 0 < x < 2 or x > 2

Interval Notation

(- \infty, 0) \cup (0, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = 0

The function domain

x < 0 or 0 < x < 2 or x > 2

f (x) = lo g_{3} (- x)

\frac{10}{( 3 x - 1 ) ^{2}}

f (x) = - 2 x^{2} + 10 x + 2

f (x) = 2 \cdot 3^{x} - 1

What is the domain of (6x)/(x^2-2x) ?
The domain of (6x)/(x^2-2x) is x<0\lor 0<x<2\lor x>2