What is the domain of f(x)=(1/7)^x ?

The domain of f(x)=(1/7)^x is -infinity <x<infinity

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domain of f(x)=(1/7)^x

domain

f (x) = (\frac{1}{7})^{x}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x ^{3} + 3 x ^{2} - 4 x}{- 4 x ^{2} - 4 x + 24}

f (x) = \frac{2 x - 7}{4 x + 6}

f (x) = \frac{( 5 x ^{3} - 4 )}{x ^{2} + 2 x - 15}

f (x) = \frac{2}{x - 1} + 3

ln (\frac{x ^{2} + 1 - 1}{x})

What is the domain of f(x)=(1/7)^x ?
The domain of f(x)=(1/7)^x is -infinity <x<infinity