What is the domain of f(x)=(x^2-36)/(x+1) ?

The domain of f(x)=(x^2-36)/(x+1) is x -1

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domain of f(x)=(x^2-36)/(x+1)

domain

f (x) = \frac{x ^{2} - 36}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = 3 + sin (x)

f (x) = 9 - (x - 4)^{2}

f (x) = lo g_{10} (4 - 2 - x)

f (x) = - 2 x^{3} + x^{2} + 1

f (x) = [- 2.3]

What is the domain of f(x)=(x^2-36)/(x+1) ?
The domain of f(x)=(x^2-36)/(x+1) is x<-1\lor x>-1