What is the domain of f(x)= x/((x^2-9)) ?

The domain of f(x)= x/((x^2-9)) is x 3

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domain of f(x)= x/((x^2-9))

domain

f (x) = \frac{x}{( x ^{2} - 9 )}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{x - 6}{x ^{2} - 25}

\frac{1728000000 x - 13824000000}{6}

3 y + x y = 2 x + 1

y = lo g_{10} (x + 2)

f (x) = \frac{x + 3}{7 - x}

What is the domain of f(x)= x/((x^2-9)) ?
The domain of f(x)= x/((x^2-9)) is x<-3\lor-3<x<3\lor x>3