What is the domain of f(x)=sqrt(4x-12) ?

The domain of f(x)=sqrt(4x-12) is x>= 3

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domain of f(x)=sqrt(4x-12)

domain

f (x) = 4 x - 12

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = 2 x + 6

y = x - 6

(0, 0), (- 2, 3)

f (x) = \frac{4 + x ^{4}}{x ^{2} - x ^{4}}

f (x) = 3 x^{2} - 6 x + 1

What is the domain of f(x)=sqrt(4x-12) ?
The domain of f(x)=sqrt(4x-12) is x>= 3