What is the domain of (3x)/(x^2-9) ?

The domain of (3x)/(x^2-9) is x 3

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domain of (3x)/(x^2-9)

domain

\frac{3 x}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = - x^{2} + 2 x - 19

- 3 cos (x)

+ 5 - \frac{2}{x}

2 x^{2} - 2

\frac{4}{( \frac{1}{x} ) - 3}

What is the domain of (3x)/(x^2-9) ?
The domain of (3x)/(x^2-9) is x<-3\lor-3<x<3\lor x>3