What is the domain of y= 1/(sqrt(x-3)) ?

The domain of y= 1/(sqrt(x-3)) is x>3

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domain of y= 1/(sqrt(x-3))

domain

y = \frac{1}{x - 3}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x > 3

f (x) = x^{\frac{4}{3}} - x^{\frac{1}{3}}

\frac{x - 1}{5}

f (x) = - x^{2} + 3 x - 1

\frac{2 y - b}{y}

\frac{7 x - 2}{x + 6}