What is the domain of f(x)=tan(x) pi/2 ?

The domain of f(x)=tan(x) pi/2 is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of f(x)=tan(x) pi/2

domain

f (x) = tan (x) \frac{π}{2}

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

[πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Solution steps

Take the denominator(s) of

tan (x) \frac{π}{2}

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

tan (x) \frac{π}{2} : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = \frac{1}{x ^{2} + 2 x - 35}

4 x + 4

f (x) = \frac{1}{3 x ^{2} + 17 x - 6}

f (x) = 6 (2)^{x - 3} + 7

f (x) = \frac{1}{18 - 3 x - x ^{2}}

What is the domain of f(x)=tan(x) pi/2 ?
The domain of f(x)=tan(x) pi/2 is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin