What is the domain of sqrt(x^2-2x) ?

The domain of sqrt(x^2-2x) is x = 2

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domain of sqrt(x^2-2x)

domain

x^{2} - 2 x

x \leq 0 or x \geq 2

Interval Notation

(- \infty, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

The function domain

x \leq 0 or x \geq 2

g (x) = 2 x + 9

f (x) = (x - 2)^{2} - 1, x \geq 0

f (x) = 2 x^{3} + 9 x^{2} - 5 x

h (x) = \frac{9 x}{x ( x ^{2} - 36 )}

f (x) = \frac{x - 5}{5 x + 5}

What is the domain of sqrt(x^2-2x) ?
The domain of sqrt(x^2-2x) is x<= 0\lor x>= 2