What is the domain of sqrt(x^2-4x) ?

The domain of sqrt(x^2-4x) is x = 4

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domain of sqrt(x^2-4x)

domain

x^{2} - 4 x

x \leq 0 or x \geq 4

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

The function domain

x \leq 0 or x \geq 4

x 8 - x^{2}

y = \frac{3 x ^{2}}{x + 5}

f (x) = 3 sin (4 x)

\frac{1}{∣ x ^{2} - 7 ∣}

x e^{- 6 x}

What is the domain of sqrt(x^2-4x) ?
The domain of sqrt(x^2-4x) is x<= 0\lor x>= 4