What is the domain of f(x)= 1/(sqrt(49-x^2)) ?

The domain of f(x)= 1/(sqrt(49-x^2)) is -7<x<7

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domain of f(x)= 1/(sqrt(49-x^2))

domain

f (x) = \frac{1}{49 - x ^{2}}

- 7 < x < 7

Interval Notation

(- 7, 7)

Solution steps

Find non-negative values for radicals:

- 7 \leq x \leq 7

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

- 7 < x < 7

y = \frac{x + 2}{x}

\frac{1}{lo g _{x} ( 2 )}

f (x) = x - 2 + 2 - x

p (x) = x - 1 + 2

f (x) = \frac{x + 9}{x - 8}

What is the domain of f(x)= 1/(sqrt(49-x^2)) ?
The domain of f(x)= 1/(sqrt(49-x^2)) is -7<x<7