What is the domain of f(x)=sqrt((x-2))+5 ?

The domain of f(x)=sqrt((x-2))+5 is x>= 2

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domain of f(x)=sqrt((x-2))+5

domain

f (x) = (x - 2) + 5

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

ln (2 + x)

f (x) = 4 - x^{2}, - 2 \leq x \leq 2

\frac{x ^{2} - 6 x + 5}{9}

f (x) = (x - 4) (x^{2} - 8 x - 32)

f (x) = x (x - 4)^{3}

What is the domain of f(x)=sqrt((x-2))+5 ?
The domain of f(x)=sqrt((x-2))+5 is x>= 2