What is the domain of f(x)=sqrt(3^{x-2)-1} ?

The domain of f(x)=sqrt(3^{x-2)-1} is x>= 2

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domain of f(x)=sqrt(3^{x-2)-1}

domain

f (x) = 3^{x - 2} - 1

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = - \frac{1}{2} \cdot lo g_{10} (- 2 - x) + 2

f (x) = \frac{4 - x}{∣ x ∣ - 1}

\frac{1}{x ( x - 1 )}

f (x) = \frac{2 x}{5 x - 1}

What is the domain of f(x)=sqrt(3^{x-2)-1} ?
The domain of f(x)=sqrt(3^{x-2)-1} is x>= 2