What is the domain of f(x)=(2x^2-13x+15)/(sqrt(x-1)) ?

The domain of f(x)=(2x^2-13x+15)/(sqrt(x-1)) is x>1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x^2-13x+15)/(sqrt(x-1))

domain

f (x) = \frac{2 x ^{2} - 13 x + 15}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

2^{x + 2} + 1

\frac{1}{x - 2}

f (x) = ∣ x - 3 ∣ + 4

f (x) = \frac{7 - 2 x ^{2}}{3 - 2 x}

\frac{3 x ^{2}}{x ^{2} + 1}

What is the domain of f(x)=(2x^2-13x+15)/(sqrt(x-1)) ?
The domain of f(x)=(2x^2-13x+15)/(sqrt(x-1)) is x>1