What is the domain of f(x)=sqrt(x+25) ?

The domain of f(x)=sqrt(x+25) is x>=-25

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domain of f(x)=sqrt(x+25)

domain

f (x) = x + 25

x \geq - 25

Interval Notation

[- 25, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 25

The function domain

x \geq - 25

\frac{x + 7}{x - 4}

f (x) = \frac{e ^{x} + 8}{x}

X^{2} + 1

f (x) = 25 - x^{2} + 3

\frac{9}{8 + x}