What is the domain of f(x)= 1/(sqrt(2x^2-5x-12)) ?

The domain of f(x)= 1/(sqrt(2x^2-5x-12)) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(sqrt(2x^2-5x-12))

domain

f (x) = \frac{1}{2 x ^{2} - 5 x - 12}

x < - \frac{3}{2} or x > 4

Interval Notation

(- \infty, - \frac{3}{2}) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq 4

Find undefined (singularity) points:

x = 4, x = - \frac{3}{2}

Combine real regions and undefined points for final function domain

x < - \frac{3}{2} or x > 4

f (x) = 3 tan (x), - π \leq x \leq π

3 x^{2} - 6 x

f (x) = \frac{18 x + 24}{x ^{2} + 5 x + 6}

16 x + 3

What is the domain of f(x)= 1/(sqrt(2x^2-5x-12)) ?
The domain of f(x)= 1/(sqrt(2x^2-5x-12)) is x<-3/2 \lor x>4