What is the domain of f(x)=sqrt(x+64) ?

The domain of f(x)=sqrt(x+64) is x>=-64

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domain of f(x)=sqrt(x+64)

domain

f (x) = x + 64

x \geq - 64

Interval Notation

[- 64, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 64

The function domain

x \geq - 64

f (x) = \frac{10 x ^{2} + x}{x ^{2} + 8}

f (x) = \frac{( n - 1 ) ( - 1 ) ^{n + 1}}{2 n + 3}

f (x) = cosh (t^{3} - 8)

f (x) = \frac{14 - 5 x}{3 x + 4}

g (x) = lo g_{2} (7 - x)