What is the domain of (x+5)/(x^2+4x-5) ?

The domain of (x+5)/(x^2+4x-5) is x 1

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domain of (x+5)/(x^2+4x-5)

domain

\frac{x + 5}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Interval Notation

(- \infty, - 5) \cup (- 5, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

\frac{2 ( x - 2 )}{x - 1}

7 x + 3

7 x + 9

f (x) = ln (x^{2} - 3 x)

\frac{3 x + 7}{x ^{2} + 5 x + 4}

What is the domain of (x+5)/(x^2+4x-5) ?
The domain of (x+5)/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1