What is the domain of sqrt(((x+1))/((x^2-4x+3))) ?

The domain of sqrt(((x+1))/((x^2-4x+3))) is -1 3

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domain of sqrt(((x+1))/((x^2-4x+3)))

domain

\frac{( x + 1 )}{( x ^{2} - 4 x + 3 )}

- 1 \leq x < 1 or x > 3

Interval Notation

[- 1, 1) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x < 1 or x > 3

Find undefined (singularity) points:

x = 3, x = 1

Combine real regions and undefined points for final function domain

- 1 \leq x < 1 or x > 3

f (x) = ln (9 - 3 t)

f (x) = \frac{3 e ^{x} - 11}{20 e ^{x} + 14}

(x + 6)^{2}

f (x) = (3 - x)^{\frac{1}{4}}

0. 4^{(5 - x)} - 4

What is the domain of sqrt(((x+1))/((x^2-4x+3))) ?
The domain of sqrt(((x+1))/((x^2-4x+3))) is -1<= x<1\lor x>3