What is the domain of arctan((1+x)/(1-x)) ?

The domain of arctan((1+x)/(1-x)) is x 1

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domain of arctan((1+x)/(1-x))

domain

arctan (\frac{1 + x}{1 - x})

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

\frac{1}{2.3 x - 7.8 x ^{2}}

f (x) = \frac{( x - 8 ) ( x - 2 )}{x - 7}

g (x) = \frac{2}{x - 2}

\frac{x - 7}{8}

\frac{4 x + 9}{x + 4}

What is the domain of arctan((1+x)/(1-x)) ?
The domain of arctan((1+x)/(1-x)) is x<1\lor x>1