What is the domain of f(x)=sqrt(x^2+1/x) ?

The domain of f(x)=sqrt(x^2+1/x) is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2+1/x)

domain

f (x) = x^{2} + \frac{1}{x}

x \leq - 1 or x > 0

Interval Notation

(- \infty, - 1] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 0

f (x) = \frac{- 8 x ^{2}}{( x - 2 ) ( x + 5 )}

f (x) = 3 + 5 + 7 x

f (x) = \frac{4 x - 3}{2}

f (x) = 2^{x + 1} - 4

f (x) = \frac{x - 1}{x ^{2} - 2 x - 8}

What is the domain of f(x)=sqrt(x^2+1/x) ?
The domain of f(x)=sqrt(x^2+1/x) is x<=-1\lor x>0