What is the domain of (sqrt(x^2-25))/(x^2+81) ?

The domain of (sqrt(x^2-25))/(x^2+81) is x = 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(x^2-25))/(x^2+81)

domain

\frac{x ^{2} - 25}{x ^{2} + 81}

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

The function domain

x \leq - 5 or x \geq 5

f (r) = arcsec (6 r^{2} - 5 r - 5)

f (x) = \frac{x ^{3} - 8}{x - 2}

(x - 1)^{2} (x + 2)

\frac{x + 8}{3 x + 4}

h (x) = \frac{9 x}{x ( x ^{2} - 49 )}

What is the domain of (sqrt(x^2-25))/(x^2+81) ?
The domain of (sqrt(x^2-25))/(x^2+81) is x<=-5\lor x>= 5