What is the asymptotes of f(x)=(x^2-4)/(4x-16) ?

The asymptotes of f(x)=(x^2-4)/(4x-16) is Vertical: x=4,Slant: y= 1/4 x+1

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asymptotes of f(x)=(x^2-4)/(4x-16)

asymptotes

f (x) = \frac{x ^{2} - 4}{4 x - 16}

Vertical : x = 4, Slant : y = \frac{1}{4} x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{4 x - 16} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 4}{4 x - 16} :

None

Slant Asymptotes of

\frac{x ^{2} - 4}{4 x - 16} : y = \frac{1}{4} x + 1

Vertical : x = 4, Slant : y = \frac{1}{4} x + 1

f (x) = x^{2} - x

f (x) = 3 - 4 x

- 23.6 (1000 sin (x) - 225) + 822.2

y = (x - 7)^{3}

f (x) = tan (2) (x - π)

What is the asymptotes of f(x)=(x^2-4)/(4x-16) ?
The asymptotes of f(x)=(x^2-4)/(4x-16) is Vertical: x=4,Slant: y= 1/4 x+1