What is the domain of f(t)=sqrt(5-4t^2) ?

The domain of f(t)=sqrt(5-4t^2) is -(sqrt(5))/2 <= t<= (sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(t)=sqrt(5-4t^2)

domain

f (t) = 5 - 4 t^{2}

- \frac{5}{2} \leq t \leq \frac{5}{2}

Interval Notation

[- \frac{5}{2}, \frac{5}{2}]

Solution steps

Find non-negative values for radicals:

- \frac{5}{2} \leq t \leq \frac{5}{2}

The function domain

- \frac{5}{2} \leq t \leq \frac{5}{2}

f (x) = (\frac{1}{3})^{x} + 3

f (x) = (\frac{1}{3})^{x} - 1

f (x) = \frac{5}{3 ^{x + 1} - 27}

f (x) = \frac{2 x - 1}{x + 5}

What is the domain of f(t)=sqrt(5-4t^2) ?
The domain of f(t)=sqrt(5-4t^2) is -(sqrt(5))/2 <= t<= (sqrt(5))/2