What is the domain of f(x)=3+sqrt(5+9x) ?

The domain of f(x)=3+sqrt(5+9x) is x>=-5/9

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domain of f(x)=3+sqrt(5+9x)

domain

f (x) = 3 + 5 + 9 x

x \geq - \frac{5}{9}

Interval Notation

[- \frac{5}{9}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{5}{9}

The function domain

x \geq - \frac{5}{9}

- ln (7 - x) + 3

5

4

f (x) = \frac{1 - 2 x}{x}

\frac{1}{x ^{2} - 7 x + 10}

What is the domain of f(x)=3+sqrt(5+9x) ?
The domain of f(x)=3+sqrt(5+9x) is x>=-5/9