What is the domain of f(x)=sqrt(x^3+3x^2-25x-75) ?

The domain of f(x)=sqrt(x^3+3x^2-25x-75) is -5 = 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^3+3x^2-25x-75)

domain

f (x) = x^{3} + 3 x^{2} - 25 x - 75

- 5 \leq x \leq - 3 or x \geq 5

Interval Notation

[- 5, - 3] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq - 3 or x \geq 5

The function domain

- 5 \leq x \leq - 3 or x \geq 5

\frac{x ^{2} - 12 x + 32}{x ^{2} - 6 x + 8}

f (x) = \frac{( x - 3 )}{( x + 5 )}

f (x) = 2 - 3 x^{2} + 7 x, - 4 \leq x \leq 8

\frac{x ^{3} - 2 x ^{2} - 3 x}{x ^{2} - 4}

x + \frac{4}{x}

What is the domain of f(x)=sqrt(x^3+3x^2-25x-75) ?
The domain of f(x)=sqrt(x^3+3x^2-25x-75) is -5<= x<=-3\lor x>= 5