What is the domain of f(x)=(sqrt(x-4))/(sqrt(x^2-9)) ?

The domain of f(x)=(sqrt(x-4))/(sqrt(x^2-9)) is x>= 4

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domain of f(x)=(sqrt(x-4))/(sqrt(x^2-9))

domain

f (x) = \frac{x - 4}{x ^{2} - 9}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x \geq 4

f (x) = \frac{5 - x}{x + 6}

f (x) = sin (sin (x))

f (x) = 3 x^{2} - 4 x - 6

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 2

f (x) = - \frac{2}{3} (5)^{x - 4} + 7

What is the domain of f(x)=(sqrt(x-4))/(sqrt(x^2-9)) ?
The domain of f(x)=(sqrt(x-4))/(sqrt(x^2-9)) is x>= 4