What is the domain of f(x)=sqrt(4x+36) ?

The domain of f(x)=sqrt(4x+36) is x>=-9

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domain of f(x)=sqrt(4x+36)

domain

f (x) = 4 x + 36

x \geq - 9

Interval Notation

[- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

The function domain

x \geq - 9

\frac{4}{x - 7}

\frac{1}{ln ( ln ( x ) ) - 1}

\frac{( - 3 + - 4 x + 1 )}{2}

\frac{2 X}{X - 1}

f (x) = \frac{1}{3} x^{2}

What is the domain of f(x)=sqrt(4x+36) ?
The domain of f(x)=sqrt(4x+36) is x>=-9