What is the domain of-1+sqrt(2-x^2) ?

The domain of-1+sqrt(2-x^2) is -sqrt(2)<= x<= sqrt(2)

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domain of-1+sqrt(2-x^2)

domain

- 1 + 2 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

\frac{8}{1 - \frac{1}{z}} - \frac{9}{1 - 0.5 \frac{1}{z}} + 2

f (x) = - 3 ∣ x ∣

f (x) = \frac{- 10}{x ^{2} - x - 20}

\frac{x + 5}{3 x ^{2} + 10 x + 3}

\frac{( x - 1 )}{x + 2}

What is the domain of-1+sqrt(2-x^2) ?
The domain of-1+sqrt(2-x^2) is -sqrt(2)<= x<= sqrt(2)