What is the domain of f(x)= 1/(4x+1) ?

The domain of f(x)= 1/(4x+1) is x -1/4

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domain of f(x)= 1/(4x+1)

domain

f (x) = \frac{1}{4 x + 1}

x < - \frac{1}{4} or x > - \frac{1}{4}

Interval Notation

(- \infty, - \frac{1}{4}) \cup (- \frac{1}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{4}

The function domain

x < - \frac{1}{4} or x > - \frac{1}{4}

4 x^{2} + 8 x + 3

f (x) = \frac{arctan ( x )}{x ^{2} - 1}

f (x) = 4 x - 5 y + 7 = 0

f (x) = \frac{x - 4}{x - 5}

f (x) = \frac{1}{4} x

What is the domain of f(x)= 1/(4x+1) ?
The domain of f(x)= 1/(4x+1) is x<-1/4 \lor x>-1/4