What is the domain of 1/(sqrt(36-x^2)) ?

The domain of 1/(sqrt(36-x^2)) is -6<x<6

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domain of 1/(sqrt(36-x^2))

domain

\frac{1}{36 - x ^{2}}

- 6 < x < 6

Interval Notation

(- 6, 6)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

- 6 < x < 6

f (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

\frac{1}{t + 2} + t + 1

y = e

y = 5 - 2 x^{2}

y = 9

What is the domain of 1/(sqrt(36-x^2)) ?
The domain of 1/(sqrt(36-x^2)) is -6<x<6