What is the domain of f(x)=arcsin((2x)/(x^2+1)) ?

The domain of f(x)=arcsin((2x)/(x^2+1)) is -infinity <x<infinity

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domain of f(x)=arcsin((2x)/(x^2+1))

domain

f (x) = arcsin (\frac{2 x}{x ^{2} + 1})

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find known functions domain restrictions:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 2.5

3 sin (x + \frac{π}{4})

f (x) = 4 x^{2}

\frac{x - 4}{x - 6}

ln (x + 2) (x - 1)^{2}

What is the domain of f(x)=arcsin((2x)/(x^2+1)) ?
The domain of f(x)=arcsin((2x)/(x^2+1)) is -infinity <x<infinity