What is the domain of f(x)=(x^2)/(9-x) ?

The domain of f(x)=(x^2)/(9-x) is x 9

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domain of f(x)=(x^2)/(9-x)

domain

f (x) = \frac{x ^{2}}{9 - x}

x < 9 or x > 9

Interval Notation

(- \infty, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9

The function domain

x < 9 or x > 9

f (x) = x^{2} + 86

f (x) = arccos (x^{2})

f (x) = 3 x^{2} - 4

\frac{4 x}{x - 2}

f (x) = \frac{x}{( 1 - x )}

What is the domain of f(x)=(x^2)/(9-x) ?
The domain of f(x)=(x^2)/(9-x) is x<9\lor x>9