What is the domain of f(x)=((x^2+3)sqrt(x-5))/(x-5) ?

The domain of f(x)=((x^2+3)sqrt(x-5))/(x-5) is x>5

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domain of f(x)=((x^2+3)sqrt(x-5))/(x-5)

domain

f (x) = \frac{( x ^{2} + 3 ) x - 5}{x - 5}

x > 5

Interval Notation

(5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

x > 5

+ 38 (e^{t} - 1)

8 x - 9

\frac{6 ( x + 4 )}{( x ^{2} - 16 )}

f (x) = \frac{x ^{2} + 2 x - 3}{3 x ^{2} + 3 x - 18}

f (x) = 2 - lo g_{2} (x)

What is the domain of f(x)=((x^2+3)sqrt(x-5))/(x-5) ?
The domain of f(x)=((x^2+3)sqrt(x-5))/(x-5) is x>5