What is the domain of 6/(x-1)+3/(x+1) ?

The domain of 6/(x-1)+3/(x+1) is x 1

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domain of 6/(x-1)+3/(x+1)

domain

\frac{6}{x - 1} + \frac{3}{x + 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{( x ^{2} - 4 )}{x - 1}

f (x) = \frac{x ^{3} + x}{x ^{2} + 4 x + 1}

\frac{x + 4}{x ( x + 12 )}

f (x) = lo g_{\frac{1}{7}} (x)

g (x) = \frac{3 x + 1}{x + 8}

What is the domain of 6/(x-1)+3/(x+1) ?
The domain of 6/(x-1)+3/(x+1) is x<-1\lor-1<x<1\lor x>1