What is the domain of f(x)= x/(x^2+12x+32) ?

The domain of f(x)= x/(x^2+12x+32) is x -4

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domain of f(x)= x/(x^2+12x+32)

domain

f (x) = \frac{x}{x ^{2} + 12 x + 32}

x < - 8 or - 8 < x < - 4 or x > - 4

Interval Notation

(- \infty, - 8) \cup (- 8, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = - 8

The function domain

x < - 8 or - 8 < x < - 4 or x > - 4

y = \frac{x - 2}{x + 2}

f (x) = arcsin (\frac{1 - x ^{2}}{1 + x ^{2}})

f (x) = 4 + 2^{1 - 2 x}

- x^{2} - x + 2

y = \frac{x - 2}{x + 3}

What is the domain of f(x)= x/(x^2+12x+32) ?
The domain of f(x)= x/(x^2+12x+32) is x<-8\lor-8<x<-4\lor x>-4