What is the domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) ?

The domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) is x>-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2-9x-36)/(sqrt(x+16))

domain

f (x) = \frac{x ^{2} - 9 x - 36}{x + 16}

x > - 16

Interval Notation

(- 16, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 16

Find undefined (singularity) points:

x = - 16

Combine real regions and undefined points for final function domain

x > - 16

1 + ln (x^{3} - 8)

f (x) = \frac{1}{1 - cos ^{2} ( x - \frac{3}{2} )}

\frac{x + 8}{3}

y = - (0.02)^{x + 6}

g (x) = \frac{x - 2}{x - 4}

What is the domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) ?
The domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) is x>-16