What is the domain of f(x)=(x^2+1)/(x^2-16) ?

The domain of f(x)=(x^2+1)/(x^2-16) is x 4

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domain of f(x)=(x^2+1)/(x^2-16)

domain

f (x) = \frac{x ^{2} + 1}{x ^{2} - 16}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

\frac{2}{t + 4}

g (x) = 3 x - 1

f (x) = \frac{1}{x - 5 - 1}

f (x) = 3 x - 1, 2 x, x \geq 1, x < 1

g (x) = 3 x + 4

What is the domain of f(x)=(x^2+1)/(x^2-16) ?
The domain of f(x)=(x^2+1)/(x^2-16) is x<-4\lor-4<x<4\lor x>4