What is the domain of f(x)=4^{log_{2}(16x)+1}=1 ?

The domain of f(x)=4^{log_{2}(16x)+1}=1 is -infinity <x<infinity

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domain of f(x)=4^{log_{2}(16x)+1}=1

domain

f (x) = 4^{l o g_{2} (16 x) + 1} = 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{( x ^{2} + 1 ) ( x + 1 )}{x - 1}

f (x) = 3 x^{2} + 1

\frac{- 2}{x - 2}

f (x) = - 3 + ln (x)

f (x) = \frac{x ^{2} + 4 x + 4}{2 x}

What is the domain of f(x)=4^{log_{2}(16x)+1}=1 ?
The domain of f(x)=4^{log_{2}(16x)+1}=1 is -infinity <x<infinity